On opening night of the drama clubs play they made $1366. They sold a total of 199 tickets. They charged $8.50 for each adult ticket and $5.00 for each child's ticket. Write a system of equations that can be used to find the number of adult tickets and the number of children's tickets sold.

Answer:a+c=199...equation 18.5 a+5 c=1,366...equation 2The number of adults tickets sold=106The number of children tickets sold=93Step-by-step explanation:a). Determine first expressionLet the number of each group be as follows;adults=achildren=ctotal number of people=199This can be expressed as;number of people=number of children+number of adultsreplacing;a+c=199...equation 1b). Determine the second expressionLet the total amount made by the opening night can be expressed as shown;total amount=(price per child ticket×number of children)+(price per adult ticket×number of adults)where;total amount=$1,366price per child ticket=$5number of children=ccost per adult=$8.5number of adults=areplacing;(8.5×a)+(5×c)=1,3668.5 a+5 c=1,366...equation 2c). Combine equation 1 and 2 and solve simultaneously1(8.5 a+5 c=1,366)-5(a+c=199)=5 a+5 c=995(8.5 a-5 a)+(5 c-5 c)=(1,366-995)3.5 a=371a=371/3.5a=106replacing the value for a in equation 1106+c=199c=199-106=93The number of adults tickets sold=106The number of children tickets sold=93